Matematika Sekolah Menengah Atas Q, Hard
4/10


jika sudut A bertolak belakang dengan Sudut B
dan sudut A = 110° sudut B = 5x + 10
nilai X = ​

Q, Hard
4/10


jika sudut A bertolak belakang dengan Sudut B
dan sudut A = 110° sudut B = 5x + 10
nilai X = ​
  • ✧༺Jawaban༻✧

20°

  • Cara pengerjaannya

A = B

  • 5x + 10° = 110°
  • 5x = 110° - 10°
  • 5x = 100°
  • X = 20°

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[tex] » \tt \: \: 5x + 10° = 110 [/tex]

[tex] » \tt \: \: 5x = 110° - 10°[/tex]

[tex] » \tt \: \: 5x = 100°[/tex]

[tex] » \tt \: \: x = 20°[/tex]

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[tex] \bold{\pink{[}\bold\color{violet}{[}\bold{\pink{A}\bold\color{violet}{E}\bold{\pink{]}\bold\color{violet}{]}}}} [/tex]

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