4/10
jika sudut A bertolak belakang dengan Sudut B
dan sudut A = 110° sudut B = 5x + 10
nilai X =
- ✧༺Jawaban༻✧
20°
- Cara pengerjaannya
A = B
- 5x + 10° = 110°
- 5x = 110° - 10°
- 5x = 100°
- X = 20°
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[tex] \colorbox{ff0000}{} \colorbox{ff4000}{}\colorbox{ff8000}{}\colorbox{ffc000}{}\colorbox{ffff00}{}\colorbox{c0ff00}{}\colorbox{80ff00}{}\colorbox{40ff00}{}\colorbox{00ff00}{}\colorbox{00ff40}{}\colorbox{00ff80}{}\colorbox{00ffc0}{}\colorbox{00ffff}{}\colorbox{00c0ff}{}\colorbox{0080ff}{}\colorbox{0040ff}{}\colorbox{0000ff}{}\colorbox{4000ff}{}\colorbox{8000ff}{}\colorbox{c000ff}{}\colorbox{ff00ff}{}\colorbox{ff00c0}{}\colorbox{ff00a0}{}\colorbox{ff0080}{}\colorbox{ff0040}{} \large \color{pink} [/tex]
[tex] » \tt \: \: 5x + 10° = 110 [/tex]
[tex] » \tt \: \: 5x = 110° - 10°[/tex]
[tex] » \tt \: \: 5x = 100°[/tex]
[tex] » \tt \: \: x = 20°[/tex]
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[tex] \bold{\pink{[}\bold\color{violet}{[}\bold{\pink{A}\bold\color{violet}{E}\bold{\pink{]}\bold\color{violet}{]}}}} [/tex]
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